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5(2^x+3)=80
We move all terms to the left:
5(2^x+3)-(80)=0
We multiply parentheses
10x+15-80=0
We add all the numbers together, and all the variables
10x-65=0
We move all terms containing x to the left, all other terms to the right
10x=65
x=65/10
x=6+1/2
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